Metamath Proof Explorer


Theorem ssel2

Description: Membership relationships follow from a subclass relationship. (Contributed by NM, 7-Jun-2004)

Ref Expression
Assertion ssel2 ( ( 𝐴 ⊆ 𝐵 ∧ 𝐶 ∈ 𝐴 ) → 𝐶 ∈ 𝐵 )

Proof

Step Hyp Ref Expression
1 ssel ⊢ ( 𝐴 ⊆ 𝐵 → ( 𝐶 ∈ 𝐴 → 𝐶 ∈ 𝐵 ) )
2 1 imp ⊢ ( ( 𝐴 ⊆ 𝐵 ∧ 𝐶 ∈ 𝐴 ) → 𝐶 ∈ 𝐵 )