Metamath Proof Explorer


Theorem ssexnelpss

Description: If there is an element of a class which is not contained in a subclass, the subclass is a proper subclass. (Contributed by AV, 29-Jan-2020)

Ref Expression
Assertion ssexnelpss ( ( 𝐴 ⊆ 𝐵 ∧ ∃ 𝑥 ∈ 𝐵 𝑥 ∉ 𝐴 ) → 𝐴 ⊊ 𝐵 )

Proof

Step Hyp Ref Expression
1 df-nel ⊢ ( 𝑥 ∉ 𝐴 ↔ ¬ 𝑥 ∈ 𝐴 )
2 ssnelpss ⊢ ( 𝐴 ⊆ 𝐵 → ( ( 𝑥 ∈ 𝐵 ∧ ¬ 𝑥 ∈ 𝐴 ) → 𝐴 ⊊ 𝐵 ) )
3 2 expdimp ⊢ ( ( 𝐴 ⊆ 𝐵 ∧ 𝑥 ∈ 𝐵 ) → ( ¬ 𝑥 ∈ 𝐴 → 𝐴 ⊊ 𝐵 ) )
4 1 3 biimtrid ⊢ ( ( 𝐴 ⊆ 𝐵 ∧ 𝑥 ∈ 𝐵 ) → ( 𝑥 ∉ 𝐴 → 𝐴 ⊊ 𝐵 ) )
5 4 rexlimdva ⊢ ( 𝐴 ⊆ 𝐵 → ( ∃ 𝑥 ∈ 𝐵 𝑥 ∉ 𝐴 → 𝐴 ⊊ 𝐵 ) )
6 5 imp ⊢ ( ( 𝐴 ⊆ 𝐵 ∧ ∃ 𝑥 ∈ 𝐵 𝑥 ∉ 𝐴 ) → 𝐴 ⊊ 𝐵 )