Metamath Proof Explorer


Theorem sspwuni

Description: Subclass relationship for power class and union. (Contributed by NM, 18-Jul-2006)

Ref Expression
Assertion sspwuni ( 𝐴 ⊆ 𝒫 𝐵 ↔ ∪ 𝐴 ⊆ 𝐵 )

Proof

Step Hyp Ref Expression
1 velpw ⊢ ( 𝑥 ∈ 𝒫 𝐵 ↔ 𝑥 ⊆ 𝐵 )
2 1 ralbii ⊢ ( ∀ 𝑥 ∈ 𝐴 𝑥 ∈ 𝒫 𝐵 ↔ ∀ 𝑥 ∈ 𝐴 𝑥 ⊆ 𝐵 )
3 dfss3 ⊢ ( 𝐴 ⊆ 𝒫 𝐵 ↔ ∀ 𝑥 ∈ 𝐴 𝑥 ∈ 𝒫 𝐵 )
4 unissb ⊢ ( ∪ 𝐴 ⊆ 𝐵 ↔ ∀ 𝑥 ∈ 𝐴 𝑥 ⊆ 𝐵 )
5 2 3 4 3bitr4i ⊢ ( 𝐴 ⊆ 𝒫 𝐵 ↔ ∪ 𝐴 ⊆ 𝐵 )