Metamath Proof Explorer


Theorem tanhaddd

Description: Addition formula for tanh. (Contributed by Jon Pennant, 9-Sep-2026)

Ref Expression
Hypotheses tanhaddd.a ⊢ ( 𝜑 → 𝐴 ∈ ℂ )
tanhaddd.b ⊢ ( 𝜑 → 𝐵 ∈ ℂ )
tanhaddd.1 ⊢ ( 𝜑 → ( cosh ‘ 𝐴 ) ≠ 0 )
tanhaddd.2 ⊢ ( 𝜑 → ( cosh ‘ 𝐵 ) ≠ 0 )
tanhaddd.3 ⊢ ( 𝜑 → ( cosh ‘ ( 𝐴 + 𝐵 ) ) ≠ 0 )
Assertion tanhaddd ( 𝜑 → ( tanh ‘ ( 𝐴 + 𝐵 ) ) = ( ( ( tanh ‘ 𝐴 ) + ( tanh ‘ 𝐵 ) ) / ( 1 + ( ( tanh ‘ 𝐴 ) · ( tanh ‘ 𝐵 ) ) ) ) )

Proof

Step Hyp Ref Expression
1 tanhaddd.a ⊢ ( 𝜑 → 𝐴 ∈ ℂ )
2 tanhaddd.b ⊢ ( 𝜑 → 𝐵 ∈ ℂ )
3 tanhaddd.1 ⊢ ( 𝜑 → ( cosh ‘ 𝐴 ) ≠ 0 )
4 tanhaddd.2 ⊢ ( 𝜑 → ( cosh ‘ 𝐵 ) ≠ 0 )
5 tanhaddd.3 ⊢ ( 𝜑 → ( cosh ‘ ( 𝐴 + 𝐵 ) ) ≠ 0 )
6 1 2 jca ⊢ ( 𝜑 → ( 𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ ) )
7 tanhadd ⊢ ( ( ( ( 𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ ) ∧ ( cosh ‘ 𝐴 ) ≠ 0 ) ∧ ( ( cosh ‘ 𝐵 ) ≠ 0 ∧ ( cosh ‘ ( 𝐴 + 𝐵 ) ) ≠ 0 ) ) → ( tanh ‘ ( 𝐴 + 𝐵 ) ) = ( ( ( tanh ‘ 𝐴 ) + ( tanh ‘ 𝐵 ) ) / ( 1 + ( ( tanh ‘ 𝐴 ) · ( tanh ‘ 𝐵 ) ) ) ) )
8 6 3 4 5 7 syl22anc ⊢ ( 𝜑 → ( tanh ‘ ( 𝐴 + 𝐵 ) ) = ( ( ( tanh ‘ 𝐴 ) + ( tanh ‘ 𝐵 ) ) / ( 1 + ( ( tanh ‘ 𝐴 ) · ( tanh ‘ 𝐵 ) ) ) ) )