Metamath Proof Explorer


Theorem tgsss2

Description: Third congruence theorem: SSS. Theorem 11.51 of Schwabhauser p. 109. (Contributed by Thierry Arnoux, 1-Aug-2020)

Ref Expression
Hypotheses tgsas.p ⊢ 𝑃 = ( Base ‘ 𝐺 )
tgsas.m ⊢ − = ( dist ‘ 𝐺 )
tgsas.i ⊢ 𝐼 = ( Itv ‘ 𝐺 )
tgsas.g ⊢ ( 𝜑 → 𝐺 ∈ TarskiG )
tgsas.a ⊢ ( 𝜑 → 𝐴 ∈ 𝑃 )
tgsas.b ⊢ ( 𝜑 → 𝐵 ∈ 𝑃 )
tgsas.c ⊢ ( 𝜑 → 𝐶 ∈ 𝑃 )
tgsas.d ⊢ ( 𝜑 → 𝐷 ∈ 𝑃 )
tgsas.e ⊢ ( 𝜑 → 𝐸 ∈ 𝑃 )
tgsas.f ⊢ ( 𝜑 → 𝐹 ∈ 𝑃 )
tgsss.1 ⊢ ( 𝜑 → ( 𝐴 − 𝐵 ) = ( 𝐷 − 𝐸 ) )
tgsss.2 ⊢ ( 𝜑 → ( 𝐵 − 𝐶 ) = ( 𝐸 − 𝐹 ) )
tgsss.3 ⊢ ( 𝜑 → ( 𝐶 − 𝐴 ) = ( 𝐹 − 𝐷 ) )
tgsss.4 ⊢ ( 𝜑 → 𝐴 ≠ 𝐵 )
tgsss.5 ⊢ ( 𝜑 → 𝐵 ≠ 𝐶 )
tgsss.6 ⊢ ( 𝜑 → 𝐶 ≠ 𝐴 )
Assertion tgsss2 ( 𝜑 → ⟨“ 𝐶 𝐴 𝐵 ”⟩ ( cgrA ‘ 𝐺 ) ⟨“ 𝐹 𝐷 𝐸 ”⟩ )

Proof

Step Hyp Ref Expression
1 tgsas.p ⊢ 𝑃 = ( Base ‘ 𝐺 )
2 tgsas.m ⊢ − = ( dist ‘ 𝐺 )
3 tgsas.i ⊢ 𝐼 = ( Itv ‘ 𝐺 )
4 tgsas.g ⊢ ( 𝜑 → 𝐺 ∈ TarskiG )
5 tgsas.a ⊢ ( 𝜑 → 𝐴 ∈ 𝑃 )
6 tgsas.b ⊢ ( 𝜑 → 𝐵 ∈ 𝑃 )
7 tgsas.c ⊢ ( 𝜑 → 𝐶 ∈ 𝑃 )
8 tgsas.d ⊢ ( 𝜑 → 𝐷 ∈ 𝑃 )
9 tgsas.e ⊢ ( 𝜑 → 𝐸 ∈ 𝑃 )
10 tgsas.f ⊢ ( 𝜑 → 𝐹 ∈ 𝑃 )
11 tgsss.1 ⊢ ( 𝜑 → ( 𝐴 − 𝐵 ) = ( 𝐷 − 𝐸 ) )
12 tgsss.2 ⊢ ( 𝜑 → ( 𝐵 − 𝐶 ) = ( 𝐸 − 𝐹 ) )
13 tgsss.3 ⊢ ( 𝜑 → ( 𝐶 − 𝐴 ) = ( 𝐹 − 𝐷 ) )
14 tgsss.4 ⊢ ( 𝜑 → 𝐴 ≠ 𝐵 )
15 tgsss.5 ⊢ ( 𝜑 → 𝐵 ≠ 𝐶 )
16 tgsss.6 ⊢ ( 𝜑 → 𝐶 ≠ 𝐴 )
17 1 2 3 4 7 5 6 10 8 9 13 11 12 16 14 15 tgsss1 ⊢ ( 𝜑 → ⟨“ 𝐶 𝐴 𝐵 ”⟩ ( cgrA ‘ 𝐺 ) ⟨“ 𝐹 𝐷 𝐸 ”⟩ )