Metamath Proof Explorer


Theorem toponcom

Description: If K is a topology on the base set of topology J , then J is a topology on the base of K . (Contributed by Mario Carneiro, 22-Aug-2015)

Ref Expression
Assertion toponcom ( ( 𝐽 ∈ Top ∧ 𝐾 ∈ ( TopOn ‘ ∪ 𝐽 ) ) → 𝐽 ∈ ( TopOn ‘ ∪ 𝐾 ) )

Proof

Step Hyp Ref Expression
1 toponuni ⊢ ( 𝐾 ∈ ( TopOn ‘ ∪ 𝐽 ) → ∪ 𝐽 = ∪ 𝐾 )
2 1 eqcomd ⊢ ( 𝐾 ∈ ( TopOn ‘ ∪ 𝐽 ) → ∪ 𝐾 = ∪ 𝐽 )
3 2 anim2i ⊢ ( ( 𝐽 ∈ Top ∧ 𝐾 ∈ ( TopOn ‘ ∪ 𝐽 ) ) → ( 𝐽 ∈ Top ∧ ∪ 𝐾 = ∪ 𝐽 ) )
4 istopon ⊢ ( 𝐽 ∈ ( TopOn ‘ ∪ 𝐾 ) ↔ ( 𝐽 ∈ Top ∧ ∪ 𝐾 = ∪ 𝐽 ) )
5 3 4 sylibr ⊢ ( ( 𝐽 ∈ Top ∧ 𝐾 ∈ ( TopOn ‘ ∪ 𝐽 ) ) → 𝐽 ∈ ( TopOn ‘ ∪ 𝐾 ) )