Metamath Proof Explorer


Theorem tr0elw

Description: Every nonempty transitive set contains the empty set (/) as an element, a consequence of Regularity. If we assume Transitive Containment, then we can omit the A e. V hypothesis, see tr0el . (Contributed by Matthew House, 6-Apr-2026)

Ref Expression
Assertion tr0elw ( ( 𝐴𝑉𝐴 ≠ ∅ ∧ Tr 𝐴 ) → ∅ ∈ 𝐴 )

Proof

Step Hyp Ref Expression
1 zfreg ( ( 𝐴𝑉𝐴 ≠ ∅ ) → ∃ 𝑥𝐴 ( 𝑥𝐴 ) = ∅ )
2 trss ( Tr 𝐴 → ( 𝑥𝐴𝑥𝐴 ) )
3 2 imp ( ( Tr 𝐴𝑥𝐴 ) → 𝑥𝐴 )
4 dfss ( 𝑥𝐴𝑥 = ( 𝑥𝐴 ) )
5 eqeq2 ( ( 𝑥𝐴 ) = ∅ → ( 𝑥 = ( 𝑥𝐴 ) ↔ 𝑥 = ∅ ) )
6 4 5 bitrid ( ( 𝑥𝐴 ) = ∅ → ( 𝑥𝐴𝑥 = ∅ ) )
7 3 6 syl5ibcom ( ( Tr 𝐴𝑥𝐴 ) → ( ( 𝑥𝐴 ) = ∅ → 𝑥 = ∅ ) )
8 eleq1 ( 𝑥 = ∅ → ( 𝑥𝐴 ↔ ∅ ∈ 𝐴 ) )
9 8 biimpcd ( 𝑥𝐴 → ( 𝑥 = ∅ → ∅ ∈ 𝐴 ) )
10 9 adantl ( ( Tr 𝐴𝑥𝐴 ) → ( 𝑥 = ∅ → ∅ ∈ 𝐴 ) )
11 7 10 syld ( ( Tr 𝐴𝑥𝐴 ) → ( ( 𝑥𝐴 ) = ∅ → ∅ ∈ 𝐴 ) )
12 11 rexlimdva ( Tr 𝐴 → ( ∃ 𝑥𝐴 ( 𝑥𝐴 ) = ∅ → ∅ ∈ 𝐴 ) )
13 1 12 syl5com ( ( 𝐴𝑉𝐴 ≠ ∅ ) → ( Tr 𝐴 → ∅ ∈ 𝐴 ) )
14 13 3impia ( ( 𝐴𝑉𝐴 ≠ ∅ ∧ Tr 𝐴 ) → ∅ ∈ 𝐴 )