Metamath Proof Explorer
Description: Equality of relations implies equality of transitive closures.
(Contributed by RP, 9-May-2020)
|
|
Ref |
Expression |
|
Assertion |
trcleq1 |
⊢ ( 𝑅 = 𝑆 → ∩ { 𝑟 ∣ ( 𝑅 ⊆ 𝑟 ∧ ( 𝑟 ∘ 𝑟 ) ⊆ 𝑟 ) } = ∩ { 𝑟 ∣ ( 𝑆 ⊆ 𝑟 ∧ ( 𝑟 ∘ 𝑟 ) ⊆ 𝑟 ) } ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
cleq1 |
⊢ ( 𝑅 = 𝑆 → ∩ { 𝑟 ∣ ( 𝑅 ⊆ 𝑟 ∧ ( 𝑟 ∘ 𝑟 ) ⊆ 𝑟 ) } = ∩ { 𝑟 ∣ ( 𝑆 ⊆ 𝑟 ∧ ( 𝑟 ∘ 𝑟 ) ⊆ 𝑟 ) } ) |