Metamath Proof Explorer


Theorem trscott

Description: The Scott's trick set of a transitive class is also transitive. (Contributed by BTernaryTau, 20-Oct-2026)

Ref Expression
Assertion trscott ( Tr 𝐴 → Tr Scott 𝐴 )

Proof

Step Hyp Ref Expression
1 r1tr ⊢ Tr ( 𝑅1 ‘ suc ∩ ( rank “ 𝐴 ) )
2 trin ⊢ ( ( Tr 𝐴 ∧ Tr ( 𝑅1 ‘ suc ∩ ( rank “ 𝐴 ) ) ) → Tr ( 𝐴 ∩ ( 𝑅1 ‘ suc ∩ ( rank “ 𝐴 ) ) ) )
3 1 2 mpan2 ⊢ ( Tr 𝐴 → Tr ( 𝐴 ∩ ( 𝑅1 ‘ suc ∩ ( rank “ 𝐴 ) ) ) )
4 dfscott3 ⊢ Scott 𝐴 = ( 𝐴 ∩ ( 𝑅1 ‘ suc ∩ ( rank “ 𝐴 ) ) )
5 treq ⊢ ( Scott 𝐴 = ( 𝐴 ∩ ( 𝑅1 ‘ suc ∩ ( rank “ 𝐴 ) ) ) → ( Tr Scott 𝐴 ↔ Tr ( 𝐴 ∩ ( 𝑅1 ‘ suc ∩ ( rank “ 𝐴 ) ) ) ) )
6 4 5 ax-mp ⊢ ( Tr Scott 𝐴 ↔ Tr ( 𝐴 ∩ ( 𝑅1 ‘ suc ∩ ( rank “ 𝐴 ) ) ) )
7 3 6 sylibr ⊢ ( Tr 𝐴 → Tr Scott 𝐴 )