Metamath Proof Explorer


Theorem ttceqd

Description: Equality deduction for transitive closure. (Contributed by Matthew House, 6-Apr-2026)

Ref Expression
Hypothesis ttceqd.1 ⊢ ( 𝜑 → 𝐴 = 𝐵 )
Assertion ttceqd ( 𝜑 → TC+ 𝐴 = TC+ 𝐵 )

Proof

Step Hyp Ref Expression
1 ttceqd.1 ⊢ ( 𝜑 → 𝐴 = 𝐵 )
2 ttceq ⊢ ( 𝐴 = 𝐵 → TC+ 𝐴 = TC+ 𝐵 )
3 1 2 syl ⊢ ( 𝜑 → TC+ 𝐴 = TC+ 𝐵 )