Metamath Proof Explorer


Theorem ttcss

Description: A transitive closure contains the transitive closures of all its subclasses. (Contributed by Matthew House, 6-Apr-2026)

Ref Expression
Assertion ttcss ( 𝐴 ⊆ TC+ 𝐵 → TC+ 𝐴 ⊆ TC+ 𝐵 )

Proof

Step Hyp Ref Expression
1 ttctr Tr TC+ 𝐵
2 ttcmin ( ( 𝐴 ⊆ TC+ 𝐵 ∧ Tr TC+ 𝐵 ) → TC+ 𝐴 ⊆ TC+ 𝐵 )
3 1 2 mpan2 ( 𝐴 ⊆ TC+ 𝐵 → TC+ 𝐴 ⊆ TC+ 𝐵 )