Metamath Proof Explorer


Theorem 1p8e9

Description: 1 + 8 = 9. (Contributed by SN, 24-Aug-2026)

Ref Expression
Assertion 1p8e9
|- ( 1 + 8 ) = 9

Proof

Step Hyp Ref Expression
1 df-8
 |-  8 = ( 7 + 1 )
2 1 oveq2i
 |-  ( 1 + 8 ) = ( 1 + ( 7 + 1 ) )
3 ax-1cn
 |-  1 e. CC
4 7cn
 |-  7 e. CC
5 3 4 3 addassi
 |-  ( ( 1 + 7 ) + 1 ) = ( 1 + ( 7 + 1 ) )
6 1p7e8
 |-  ( 1 + 7 ) = 8
7 6 oveq1i
 |-  ( ( 1 + 7 ) + 1 ) = ( 8 + 1 )
8 8p1e9
 |-  ( 8 + 1 ) = 9
9 7 8 eqtri
 |-  ( ( 1 + 7 ) + 1 ) = 9
10 2 5 9 3eqtr2i
 |-  ( 1 + 8 ) = 9