Metamath Proof Explorer


Theorem 1p8e9

Description: 1 + 8 = 9. (Contributed by SN, 24-Aug-2026)

Ref Expression
Assertion 1p8e9 ( 1 + 8 ) = 9

Proof

Step Hyp Ref Expression
1 df-8 8 = ( 7 + 1 )
2 1 oveq2i ( 1 + 8 ) = ( 1 + ( 7 + 1 ) )
3 ax-1cn 1 ∈ ℂ
4 7cn 7 ∈ ℂ
5 3 4 3 addassi ( ( 1 + 7 ) + 1 ) = ( 1 + ( 7 + 1 ) )
6 1p7e8 ( 1 + 7 ) = 8
7 6 oveq1i ( ( 1 + 7 ) + 1 ) = ( 8 + 1 )
8 8p1e9 ( 8 + 1 ) = 9
9 7 8 eqtri ( ( 1 + 7 ) + 1 ) = 9
10 2 5 9 3eqtr2i ( 1 + 8 ) = 9