Metamath Proof Explorer


Theorem 3com12

Description: Commutation in antecedent. Swap 1st and 2nd. (Contributed by NM, 28-Jan-1996) (Proof shortened by Andrew Salmon, 13-May-2011) (Proof shortened by Wolf Lammen, 22-Jun-2022)

Ref Expression
Hypothesis 3exp.1
|- ( ( ph /\ ps /\ ch ) -> th )
Assertion 3com12
|- ( ( ps /\ ph /\ ch ) -> th )

Proof

Step Hyp Ref Expression
1 3exp.1
 |-  ( ( ph /\ ps /\ ch ) -> th )
2 1 3exp
 |-  ( ph -> ( ps -> ( ch -> th ) ) )
3 2 3imp21
 |-  ( ( ps /\ ph /\ ch ) -> th )