Metamath Proof Explorer


Theorem 3eqtrd

Description: A deduction from three chained equalities. (Contributed by NM, 29-Oct-1995)

Ref Expression
Hypotheses 3eqtrd.1
|- ( ph -> A = B )
3eqtrd.2
|- ( ph -> B = C )
3eqtrd.3
|- ( ph -> C = D )
Assertion 3eqtrd
|- ( ph -> A = D )

Proof

Step Hyp Ref Expression
1 3eqtrd.1
 |-  ( ph -> A = B )
2 3eqtrd.2
 |-  ( ph -> B = C )
3 3eqtrd.3
 |-  ( ph -> C = D )
4 2 3 eqtrd
 |-  ( ph -> B = D )
5 1 4 eqtrd
 |-  ( ph -> A = D )