Metamath Proof Explorer


Theorem 5p1e6

Description: 5 + 1 = 6. (Contributed by Mario Carneiro, 18-Apr-2015)

Ref Expression
Assertion 5p1e6
|- ( 5 + 1 ) = 6

Proof

Step Hyp Ref Expression
1 df-6
 |-  6 = ( 5 + 1 )
2 1 eqcomi
 |-  ( 5 + 1 ) = 6