Metamath Proof Explorer


Theorem alseu-no-surprise

Description: Demonstrate that there is never a "surprise" when using the "all some one" quantifier, that is, it is never possible for the consequent to be both always true and always false. This follows from als-no-surprise by alseuals . For a contrast, see alimp-surprise . (Contributed by David A. Wheeler, 21-Jul-2026)

Ref Expression
Assertion alseu-no-surprise
|- -. ( AE! x ( ph -> ps ) /\ AE! x ( ph -> -. ps ) )

Proof

Step Hyp Ref Expression
1 als-no-surprise
 |-  -. ( AE x ( ph -> ps ) /\ AE x ( ph -> -. ps ) )
2 alseuals
 |-  ( AE! x ( ph -> ps ) -> AE x ( ph -> ps ) )
3 alseuals
 |-  ( AE! x ( ph -> -. ps ) -> AE x ( ph -> -. ps ) )
4 2 3 anim12i
 |-  ( ( AE! x ( ph -> ps ) /\ AE! x ( ph -> -. ps ) ) -> ( AE x ( ph -> ps ) /\ AE x ( ph -> -. ps ) ) )
5 1 4 mto
 |-  -. ( AE! x ( ph -> ps ) /\ AE! x ( ph -> -. ps ) )