Description: "All some one" implies "all some": requiring exactly one witness is stronger than requiring at least one. Any consequence of an allsome statement is therefore a consequence of the corresponding "all some one" statement, which is how alseu-no-surprise is proved. (Contributed by David A. Wheeler, 21-Jul-2026)
| Ref | Expression | ||
|---|---|---|---|
| Assertion | alseuals | |- ( AE! x ( ph -> ps ) -> AE x ( ph -> ps ) ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | euex | |- ( E! x ph -> E. x ph ) |
|
| 2 | 1 | anim2i | |- ( ( A. x ( ph -> ps ) /\ E! x ph ) -> ( A. x ( ph -> ps ) /\ E. x ph ) ) |
| 3 | df-alseu | |- ( AE! x ( ph -> ps ) <-> ( A. x ( ph -> ps ) /\ E! x ph ) ) |
|
| 4 | df-als | |- ( AE x ( ph -> ps ) <-> ( A. x ( ph -> ps ) /\ E. x ph ) ) |
|
| 5 | 2 3 4 | 3imtr4i | |- ( AE! x ( ph -> ps ) -> AE x ( ph -> ps ) ) |