Metamath Proof Explorer


Theorem alseuals

Description: "All some one" implies "all some": requiring exactly one witness is stronger than requiring at least one. Any consequence of an allsome statement is therefore a consequence of the corresponding "all some one" statement, which is how alseu-no-surprise is proved. (Contributed by David A. Wheeler, 21-Jul-2026)

Ref Expression
Assertion alseuals ( ∀∃! 𝑥 ( 𝜑 → 𝜓 ) → ∀∃ 𝑥 ( 𝜑 → 𝜓 ) )

Proof

Step Hyp Ref Expression
1 euex ⊢ ( ∃! 𝑥 𝜑 → ∃ 𝑥 𝜑 )
2 1 anim2i ⊢ ( ( ∀ 𝑥 ( 𝜑 → 𝜓 ) ∧ ∃! 𝑥 𝜑 ) → ( ∀ 𝑥 ( 𝜑 → 𝜓 ) ∧ ∃ 𝑥 𝜑 ) )
3 df-alseu ⊢ ( ∀∃! 𝑥 ( 𝜑 → 𝜓 ) ↔ ( ∀ 𝑥 ( 𝜑 → 𝜓 ) ∧ ∃! 𝑥 𝜑 ) )
4 df-als ⊢ ( ∀∃ 𝑥 ( 𝜑 → 𝜓 ) ↔ ( ∀ 𝑥 ( 𝜑 → 𝜓 ) ∧ ∃ 𝑥 𝜑 ) )
5 2 3 4 3imtr4i ⊢ ( ∀∃! 𝑥 ( 𝜑 → 𝜓 ) → ∀∃ 𝑥 ( 𝜑 → 𝜓 ) )