Metamath Proof Explorer


Theorem alseu2d

Description: Deduction rule: Given "all some one" applied to a top-level inference, you can extract the "exactly one" part. (Contributed by David A. Wheeler, 21-Jul-2026)

Ref Expression
Hypothesis alseu2d.1
|- ( ph -> AE! x ( ps -> ch ) )
Assertion alseu2d
|- ( ph -> E! x ps )

Proof

Step Hyp Ref Expression
1 alseu2d.1
 |-  ( ph -> AE! x ( ps -> ch ) )
2 df-alseu
 |-  ( AE! x ( ps -> ch ) <-> ( A. x ( ps -> ch ) /\ E! x ps ) )
3 1 2 sylib
 |-  ( ph -> ( A. x ( ps -> ch ) /\ E! x ps ) )
4 3 simprd
 |-  ( ph -> E! x ps )