Metamath Proof Explorer


Theorem anim12d

Description: Conjoin antecedents and consequents in a deduction. (Contributed by NM, 3-Apr-1994) (Proof shortened by Wolf Lammen, 18-Dec-2013)

Ref Expression
Hypotheses anim12d.1
|- ( ph -> ( ps -> ch ) )
anim12d.2
|- ( ph -> ( th -> ta ) )
Assertion anim12d
|- ( ph -> ( ( ps /\ th ) -> ( ch /\ ta ) ) )

Proof

Step Hyp Ref Expression
1 anim12d.1
 |-  ( ph -> ( ps -> ch ) )
2 anim12d.2
 |-  ( ph -> ( th -> ta ) )
3 idd
 |-  ( ph -> ( ( ch /\ ta ) -> ( ch /\ ta ) ) )
4 1 2 3 syl2and
 |-  ( ph -> ( ( ps /\ th ) -> ( ch /\ ta ) ) )