Theorem breq1d

Description: Equality deduction for a binary relation. (Contributed by NM, 8-Feb-1996)

	Ref	Expression
Hypothesis	breq1d.1	|- ( ph -> A = B )
Assertion	breq1d	|- ( ph -> ( A R C <-> B R C ) )

Proof

Step	Hyp	Ref	Expression
1		breq1d.1	|- ( ph -> A = B )
2		breq1	|- ( A = B -> ( A R C <-> B R C ) )
3	1 2	syl	|- ( ph -> ( A R C <-> B R C ) )