Metamath Proof Explorer


Theorem breq1d

Description: Equality deduction for a binary relation. (Contributed by NM, 8-Feb-1996)

Ref Expression
Hypothesis breq1d.1 φ A = B
Assertion breq1d φ A R C B R C

Proof

Step Hyp Ref Expression
1 breq1d.1 φ A = B
2 breq1 A = B A R C B R C
3 1 2 syl φ A R C B R C