Metamath Proof Explorer


Theorem cbvexvOLD

Description: Obsolete version of cbvexv as of 11-Sep-2023. (Contributed by NM, 21-Jun-1993) Remove dependency on ax-10 . (Revised by Wolf Lammen, 17-Jul-2021) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Hypothesis cbvalv.1
|- ( x = y -> ( ph <-> ps ) )
Assertion cbvexvOLD
|- ( E. x ph <-> E. y ps )

Proof

Step Hyp Ref Expression
1 cbvalv.1
 |-  ( x = y -> ( ph <-> ps ) )
2 1 notbid
 |-  ( x = y -> ( -. ph <-> -. ps ) )
3 2 cbvalv
 |-  ( A. x -. ph <-> A. y -. ps )
4 alnex
 |-  ( A. x -. ph <-> -. E. x ph )
5 alnex
 |-  ( A. y -. ps <-> -. E. y ps )
6 3 4 5 3bitr3i
 |-  ( -. E. x ph <-> -. E. y ps )
7 6 con4bii
 |-  ( E. x ph <-> E. y ps )