Metamath Proof Explorer


Theorem chsupcl

Description: Closure of supremum of subset of CH . Definition of supremum in Proposition 1 of Kalmbach p. 65. Shows that CH is a complete lattice. Also part of Definition 3.4-1 in MegPav2000 p. 2345 (PDF p. 8). (Contributed by NM, 10-Nov-1999) (New usage is discouraged.)

Ref Expression
Assertion chsupcl
|- ( A C_ CH -> ( \/H ` A ) e. CH )

Proof

Step Hyp Ref Expression
1 chsspwh
 |-  CH C_ ~P ~H
2 sstr2
 |-  ( A C_ CH -> ( CH C_ ~P ~H -> A C_ ~P ~H ) )
3 1 2 mpi
 |-  ( A C_ CH -> A C_ ~P ~H )
4 hsupcl
 |-  ( A C_ ~P ~H -> ( \/H ` A ) e. CH )
5 3 4 syl
 |-  ( A C_ CH -> ( \/H ` A ) e. CH )