Metamath Proof Explorer


Theorem chsupcl

Description: Closure of supremum of subset of CH . Definition of supremum in Proposition 1 of Kalmbach p. 65. Shows that CH is a complete lattice. Also part of Definition 3.4-1 in MegPav2000 p. 2345 (PDF p. 8). (Contributed by NM, 10-Nov-1999) (New usage is discouraged.)

Ref Expression
Assertion chsupcl ( 𝐴 ⊆ Cℋ → ( ∨ℋ ‘ 𝐴 ) ∈ Cℋ )

Proof

Step Hyp Ref Expression
1 chsspwh ⊢ Cℋ ⊆ 𝒫 ℋ
2 sstr2 ⊢ ( 𝐴 ⊆ Cℋ → ( Cℋ ⊆ 𝒫 ℋ → 𝐴 ⊆ 𝒫 ℋ ) )
3 1 2 mpi ⊢ ( 𝐴 ⊆ Cℋ → 𝐴 ⊆ 𝒫 ℋ )
4 hsupcl ⊢ ( 𝐴 ⊆ 𝒫 ℋ → ( ∨ℋ ‘ 𝐴 ) ∈ Cℋ )
5 3 4 syl ⊢ ( 𝐴 ⊆ Cℋ → ( ∨ℋ ‘ 𝐴 ) ∈ Cℋ )