Metamath Proof Explorer


Theorem dmec2d

Description: Equality of the coset of B and the coset of C implies equivalence of domain elementhood (equivalence is not necessary as opposed to ereldm ). (Contributed by Peter Mazsa, 12-Oct-2018)

Ref Expression
Hypothesis dmec2d.1
|- ( ph -> [ B ] R = [ C ] R )
Assertion dmec2d
|- ( ph -> ( B e. dom R <-> C e. dom R ) )

Proof

Step Hyp Ref Expression
1 dmec2d.1
 |-  ( ph -> [ B ] R = [ C ] R )
2 eqidd
 |-  ( ph -> dom R = dom R )
3 2 1 dmecd
 |-  ( ph -> ( B e. dom R <-> C e. dom R ) )