Metamath Proof Explorer


Theorem dmeqi

Description: Equality inference for domain. (Contributed by NM, 4-Mar-2004)

Ref Expression
Hypothesis dmeqi.1
|- A = B
Assertion dmeqi
|- dom A = dom B

Proof

Step Hyp Ref Expression
1 dmeqi.1
 |-  A = B
2 dmeq
 |-  ( A = B -> dom A = dom B )
3 1 2 ax-mp
 |-  dom A = dom B