Metamath Proof Explorer


Theorem eceq2d

Description: Equality theorem for the A -coset and B -coset of C , deduction version. (Contributed by Peter Mazsa, 23-Apr-2021)

Ref Expression
Hypothesis eceq2d.1
|- ( ph -> A = B )
Assertion eceq2d
|- ( ph -> [ C ] A = [ C ] B )

Proof

Step Hyp Ref Expression
1 eceq2d.1
 |-  ( ph -> A = B )
2 eceq2
 |-  ( A = B -> [ C ] A = [ C ] B )
3 1 2 syl
 |-  ( ph -> [ C ] A = [ C ] B )