Metamath Proof Explorer
Description: Deduction that substitutes equal classes into membership. (Contributed by NM, 14-Dec-2004)
|
|
Ref |
Expression |
|
Hypotheses |
eleqtrrd.1 |
|- ( ph -> A e. B ) |
|
|
eleqtrrd.2 |
|- ( ph -> C = B ) |
|
Assertion |
eleqtrrd |
|- ( ph -> A e. C ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
eleqtrrd.1 |
|- ( ph -> A e. B ) |
2 |
|
eleqtrrd.2 |
|- ( ph -> C = B ) |
3 |
2
|
eqcomd |
|- ( ph -> B = C ) |
4 |
1 3
|
eleqtrd |
|- ( ph -> A e. C ) |