Metamath Proof Explorer


Theorem elfvexd

Description: If a function value has a member, then its argument is a set. Deduction form of elfvex . (An artifact of our function value definition.) (Contributed by David Moews, 1-May-2017)

Ref Expression
Hypothesis elfvexd.1
|- ( ph -> A e. ( B ` C ) )
Assertion elfvexd
|- ( ph -> C e. _V )

Proof

Step Hyp Ref Expression
1 elfvexd.1
 |-  ( ph -> A e. ( B ` C ) )
2 elfvex
 |-  ( A e. ( B ` C ) -> C e. _V )
3 1 2 syl
 |-  ( ph -> C e. _V )