Metamath Proof Explorer


Theorem eqeq1i

Description: Inference from equality to equivalence of equalities. (Contributed by NM, 15-Jul-1993)

Ref Expression
Hypothesis eqeq1i.1
|- A = B
Assertion eqeq1i
|- ( A = C <-> B = C )

Proof

Step Hyp Ref Expression
1 eqeq1i.1
 |-  A = B
2 eqeq1
 |-  ( A = B -> ( A = C <-> B = C ) )
3 1 2 ax-mp
 |-  ( A = C <-> B = C )