Metamath Proof Explorer


Theorem eqrabi

Description: Class element of a restricted class abstraction. (Contributed by Peter Mazsa, 24-Jul-2021)

Ref Expression
Hypothesis eqrabi.1
|- ( x e. A <-> ( x e. B /\ ph ) )
Assertion eqrabi
|- A = { x e. B | ph }

Proof

Step Hyp Ref Expression
1 eqrabi.1
 |-  ( x e. A <-> ( x e. B /\ ph ) )
2 1 eqabi
 |-  A = { x | ( x e. B /\ ph ) }
3 df-rab
 |-  { x e. B | ph } = { x | ( x e. B /\ ph ) }
4 2 3 eqtr4i
 |-  A = { x e. B | ph }