Theorem exp56

Description: An exportation inference. (Contributed by Jeff Hankins, 7-Jul-2009)

	Ref	Expression
Hypothesis	exp56.1	|- ( ( ( ( ph /\ ps ) /\ ch ) /\ ( th /\ ta ) ) -> et )
Assertion	exp56	|- ( ph -> ( ps -> ( ch -> ( th -> ( ta -> et ) ) ) ) )

Proof

Step	Hyp	Ref	Expression
1		exp56.1	|- ( ( ( ( ph /\ ps ) /\ ch ) /\ ( th /\ ta ) ) -> et )
2	1	ex	|- ( ( ( ph /\ ps ) /\ ch ) -> ( ( th /\ ta ) -> et ) )
3	2	exp5d	|- ( ph -> ( ps -> ( ch -> ( th -> ( ta -> et ) ) ) ) )