Metamath Proof Explorer

Theorem expdcom

Description: Commuted form of expd . (Contributed by Alan Sare, 18-Mar-2012) Shorten expd . (Revised by Wolf Lammen, 28-Jul-2022)

Ref Expression
Hypothesis expd.1 
|- ( ph -> ( ( ps /\ ch ) -> th ) )
Assertion expdcom 
|- ( ps -> ( ch -> ( ph -> th ) ) )

Proof

Step Hyp Ref Expression
1 expd.1 
 |-  ( ph -> ( ( ps /\ ch ) -> th ) )
2 1 com12 
 |-  ( ( ps /\ ch ) -> ( ph -> th ) )
3 2 ex 
 |-  ( ps -> ( ch -> ( ph -> th ) ) )