Theorem expdcom

Description: Commuted form of expd . (Contributed by Alan Sare, 18-Mar-2012) Shorten expd . (Revised by Wolf Lammen, 28-Jul-2022)

	Ref	Expression
Hypothesis	expd.1	⊢ ( 𝜑 → ( ( 𝜓 ∧ 𝜒 ) → 𝜃 ) )
Assertion	expdcom	⊢ ( 𝜓 → ( 𝜒 → ( 𝜑 → 𝜃 ) ) )

Proof

Step	Hyp	Ref	Expression
1		expd.1	⊢ ( 𝜑 → ( ( 𝜓 ∧ 𝜒 ) → 𝜃 ) )
2	1	com12	⊢ ( ( 𝜓 ∧ 𝜒 ) → ( 𝜑 → 𝜃 ) )
3	2	ex	⊢ ( 𝜓 → ( 𝜒 → ( 𝜑 → 𝜃 ) ) )