Metamath Proof Explorer


Theorem frege36

Description: The case in which ps is denied, -. ph is affirmed, and ph is affirmed does not occur. If ph occurs, then (at least) one of the two, ph or ps , takes place (no matter what ps might be). Identical to pm2.24 . Proposition 36 of Frege1879 p. 45. (Contributed by RP, 24-Dec-2019) (Proof modification is discouraged.)

Ref Expression
Assertion frege36
|- ( ph -> ( -. ph -> ps ) )

Proof

Step Hyp Ref Expression
1 ax-frege1
 |-  ( ph -> ( -. ps -> ph ) )
2 frege34
 |-  ( ( ph -> ( -. ps -> ph ) ) -> ( ph -> ( -. ph -> ps ) ) )
3 1 2 ax-mp
 |-  ( ph -> ( -. ph -> ps ) )