Metamath Proof Explorer


Theorem fsumconst1

Description: The sum of 1 over a finite set equals the size of the set. (Contributed by AV, 10-Apr-2026)

Ref Expression
Assertion fsumconst1
|- ( A e. Fin -> sum_ k e. A 1 = ( # ` A ) )

Proof

Step Hyp Ref Expression
1 1cnd
 |-  ( A e. Fin -> 1 e. CC )
2 fsumconst
 |-  ( ( A e. Fin /\ 1 e. CC ) -> sum_ k e. A 1 = ( ( # ` A ) x. 1 ) )
3 1 2 mpdan
 |-  ( A e. Fin -> sum_ k e. A 1 = ( ( # ` A ) x. 1 ) )
4 hashcl
 |-  ( A e. Fin -> ( # ` A ) e. NN0 )
5 4 nn0cnd
 |-  ( A e. Fin -> ( # ` A ) e. CC )
6 5 mulridd
 |-  ( A e. Fin -> ( ( # ` A ) x. 1 ) = ( # ` A ) )
7 3 6 eqtrd
 |-  ( A e. Fin -> sum_ k e. A 1 = ( # ` A ) )