Metamath Proof Explorer


Theorem funrnex

Description: If the domain of a function exists, so does its range. Part of Theorem 4.15(v) of Monk1 p. 46. This theorem is derived using the Axiom of Replacement in the form of funex . (Contributed by NM, 11-Nov-1995)

Ref Expression
Assertion funrnex
|- ( dom F e. B -> ( Fun F -> ran F e. _V ) )

Proof

Step Hyp Ref Expression
1 funex
 |-  ( ( Fun F /\ dom F e. B ) -> F e. _V )
2 1 ex
 |-  ( Fun F -> ( dom F e. B -> F e. _V ) )
3 rnexg
 |-  ( F e. _V -> ran F e. _V )
4 2 3 syl6com
 |-  ( dom F e. B -> ( Fun F -> ran F e. _V ) )