Metamath Proof Explorer


Theorem funex

Description: If the domain of a function exists, so does the function. Part of Theorem 4.15(v) of Monk1 p. 46. This theorem is derived using the Axiom of Replacement in the form of fnex . (Note: Any resemblance between F.U.N.E.X. and "Have You Any Eggs" is purely a coincidence originated by Swedish chefs.) (Contributed by NM, 11-Nov-1995)

Ref Expression
Assertion funex
|- ( ( Fun F /\ dom F e. B ) -> F e. _V )

Proof

Step Hyp Ref Expression
1 funfn
 |-  ( Fun F <-> F Fn dom F )
2 fnex
 |-  ( ( F Fn dom F /\ dom F e. B ) -> F e. _V )
3 1 2 sylanb
 |-  ( ( Fun F /\ dom F e. B ) -> F e. _V )