Metamath Proof Explorer


Theorem funex

Description: If the domain of a function exists, so does the function. Part of Theorem 4.15(v) of Monk1 p. 46. This theorem is derived using the Axiom of Replacement in the form of fnex . (Note: Any resemblance between F.U.N.E.X. and "Have You Any Eggs" is purely a coincidence originated by Swedish chefs.) (Contributed by NM, 11-Nov-1995)

Ref Expression
Assertion funex ( ( Fun 𝐹 ∧ dom 𝐹𝐵 ) → 𝐹 ∈ V )

Proof

Step Hyp Ref Expression
1 funfn ( Fun 𝐹𝐹 Fn dom 𝐹 )
2 fnex ( ( 𝐹 Fn dom 𝐹 ∧ dom 𝐹𝐵 ) → 𝐹 ∈ V )
3 1 2 sylanb ( ( Fun 𝐹 ∧ dom 𝐹𝐵 ) → 𝐹 ∈ V )