Metamath Proof Explorer


Theorem hadifpOLD

Description: Obsolete version of hadifp as of 10-Aug-2026. (Contributed by BJ, 11-Aug-2020) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Assertion hadifpOLD
|- ( hadd ( ph , ps , ch ) <-> if- ( ph , ( ps <-> ch ) , ( ps \/_ ch ) ) )

Proof

Step Hyp Ref Expression
1 had1OLD
 |-  ( ph -> ( hadd ( ph , ps , ch ) <-> ( ps <-> ch ) ) )
2 had0OLD
 |-  ( -. ph -> ( hadd ( ph , ps , ch ) <-> ( ps \/_ ch ) ) )
3 1 2 casesifp
 |-  ( hadd ( ph , ps , ch ) <-> if- ( ph , ( ps <-> ch ) , ( ps \/_ ch ) ) )