Metamath Proof Explorer


Theorem hadifpOLD

Description: Obsolete version of hadifp as of 10-Aug-2026. (Contributed by BJ, 11-Aug-2020) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Assertion hadifpOLD ( hadd ( 𝜑 , 𝜓 , 𝜒 ) ↔ if- ( 𝜑 , ( 𝜓𝜒 ) , ( 𝜓𝜒 ) ) )

Proof

Step Hyp Ref Expression
1 had1OLD ( 𝜑 → ( hadd ( 𝜑 , 𝜓 , 𝜒 ) ↔ ( 𝜓𝜒 ) ) )
2 had0OLD ( ¬ 𝜑 → ( hadd ( 𝜑 , 𝜓 , 𝜒 ) ↔ ( 𝜓𝜒 ) ) )
3 1 2 casesifp ( hadd ( 𝜑 , 𝜓 , 𝜒 ) ↔ if- ( 𝜑 , ( 𝜓𝜒 ) , ( 𝜓𝜒 ) ) )