Metamath Proof Explorer


Theorem impcomd

Description: Importation deduction with commuted antecedents. (Contributed by Peter Mazsa, 24-Sep-2022) (Proof shortened by Wolf Lammen, 22-Oct-2022)

Ref Expression
Hypothesis impd.1
|- ( ph -> ( ps -> ( ch -> th ) ) )
Assertion impcomd
|- ( ph -> ( ( ch /\ ps ) -> th ) )

Proof

Step Hyp Ref Expression
1 impd.1
 |-  ( ph -> ( ps -> ( ch -> th ) ) )
2 1 com23
 |-  ( ph -> ( ch -> ( ps -> th ) ) )
3 2 impd
 |-  ( ph -> ( ( ch /\ ps ) -> th ) )