Metamath Proof Explorer


Theorem impd

Description: Importation deduction. (Contributed by NM, 31-Mar-1994)

Ref Expression
Hypothesis impd.1
|- ( ph -> ( ps -> ( ch -> th ) ) )
Assertion impd
|- ( ph -> ( ( ps /\ ch ) -> th ) )

Proof

Step Hyp Ref Expression
1 impd.1
 |-  ( ph -> ( ps -> ( ch -> th ) ) )
2 1 com3l
 |-  ( ps -> ( ch -> ( ph -> th ) ) )
3 2 imp
 |-  ( ( ps /\ ch ) -> ( ph -> th ) )
4 3 com12
 |-  ( ph -> ( ( ps /\ ch ) -> th ) )