Metamath Proof Explorer


Theorem ineq2i

Description: Equality inference for intersection of two classes. (Contributed by NM, 26-Dec-1993)

Ref Expression
Hypothesis ineq1i.1
|- A = B
Assertion ineq2i
|- ( C i^i A ) = ( C i^i B )

Proof

Step Hyp Ref Expression
1 ineq1i.1
 |-  A = B
2 ineq2
 |-  ( A = B -> ( C i^i A ) = ( C i^i B ) )
3 1 2 ax-mp
 |-  ( C i^i A ) = ( C i^i B )