Metamath Proof Explorer


Theorem ltsubs1d

Description: Subtraction from both sides of surreal less-than. (Contributed by Scott Fenton, 5-Feb-2025)

Ref Expression
Hypotheses ltsubsd.1
|- ( ph -> A e. No )
ltsubsd.2
|- ( ph -> B e. No )
ltsubsd.3
|- ( ph -> C e. No )
Assertion ltsubs1d
|- ( ph -> ( A  ( A -s C ) 

Proof

Step Hyp Ref Expression
1 ltsubsd.1
 |-  ( ph -> A e. No )
2 ltsubsd.2
 |-  ( ph -> B e. No )
3 ltsubsd.3
 |-  ( ph -> C e. No )
4 ltsubs1
 |-  ( ( A e. No /\ B e. No /\ C e. No ) -> ( A  ( A -s C ) 
5 1 2 3 4 syl3anc
 |-  ( ph -> ( A  ( A -s C )