Metamath Proof Explorer


Theorem merlem2

Description: Step 4 of Meredith's proof of Lukasiewicz axioms from his sole axiom. (Contributed by NM, 14-Dec-2002) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Assertion merlem2
|- ( ( ( ph -> ph ) -> ch ) -> ( th -> ch ) )

Proof

Step Hyp Ref Expression
1 merlem1
 |-  ( ( ( ( ch -> ch ) -> ( -. ph -> -. th ) ) -> ph ) -> ( ph -> ph ) )
2 meredith
 |-  ( ( ( ( ( ch -> ch ) -> ( -. ph -> -. th ) ) -> ph ) -> ( ph -> ph ) ) -> ( ( ( ph -> ph ) -> ch ) -> ( th -> ch ) ) )
3 1 2 ax-mp
 |-  ( ( ( ph -> ph ) -> ch ) -> ( th -> ch ) )