Metamath Proof Explorer


Theorem negidd

Description: Addition of a number and its negative. (Contributed by Mario Carneiro, 27-May-2016)

Ref Expression
Hypothesis negidd.1
|- ( ph -> A e. CC )
Assertion negidd
|- ( ph -> ( A + -u A ) = 0 )

Proof

Step Hyp Ref Expression
1 negidd.1
 |-  ( ph -> A e. CC )
2 negid
 |-  ( A e. CC -> ( A + -u A ) = 0 )
3 1 2 syl
 |-  ( ph -> ( A + -u A ) = 0 )