Metamath Proof Explorer


Theorem nfccdeq

Description: Variation of nfcdeq for classes. Usage of this theorem is discouraged because it depends on ax-13 . (Contributed by Mario Carneiro, 11-Aug-2016) Avoid ax-11 . (Revised by Gino Giotto, 19-May-2023) (New usage is discouraged.)

Ref Expression
Hypotheses nfccdeq.1
|- F/_ x A
nfccdeq.2
|- CondEq ( x = y -> A = B )
Assertion nfccdeq
|- A = B

Proof

Step Hyp Ref Expression
1 nfccdeq.1
 |-  F/_ x A
2 nfccdeq.2
 |-  CondEq ( x = y -> A = B )
3 1 nfcri
 |-  F/ x z e. A
4 eqid
 |-  z = z
5 4 cdeqth
 |-  CondEq ( x = y -> z = z )
6 5 2 cdeqel
 |-  CondEq ( x = y -> ( z e. A <-> z e. B ) )
7 3 6 nfcdeq
 |-  ( z e. A <-> z e. B )
8 7 eqriv
 |-  A = B